Suppose 23.00 g ammonium chloride 53.491 (g/mol) dissolves in water in a calorimeter to form 100.00 g of solution.The temperature decreases by 10.75$\degree$C.Calculate the $\Delta$H of solution of NH₄Cl in kJ/mol.Assume the specific heats of the solution and of the empty calorimeter are (4.18 J/g .$\degree$C) and 0.170 kJ/$\degree$C, respectively.

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The Answer of Suppose 23.00 g ammonium chloride 53.491 (g/mol) dissolves in water in a calorimeter to form 100.00 g of solution.The temperature decreases by 10.75$\degree$C.Calculate the $\Delta$H of solution of NH₄Cl in kJ/mol.Assume the specific heats of the solution and of the empty calorimeter are (4.18 J/g .$\degree$C) and 0.170 kJ/$\degree$C, respectively.

Suppose 23 °\degree° CCalculate The G Δ\DeltaΔ H of Solution of NH4Cl in KJ/mol

Suppose 23 $\degree$ CCalculate The G $\Delta$ H of Solution of NH₄Cl in KJ/mol