Solve the problem. Use the critical-value approach.
-A machine that fills soda bottles is supposed to fill them to a mean volume of 16.2 fluid ounces. A random sample of 20 filled bottles produced the following volumes in fluid ounces: $$\begin{array}{l}
\begin{array} { l l l l l l l l l l }
16.3 & 15.9 & 16.7 & 15.3 & 17.1 & 16.4 & 3.9 & 15.9 & 16.2 & 3.4 \
16.4 & 8.2 & 15.5 & 16.5 & 16.0 & 16.3 & 15.8 & 16.7 & 16.5 & 15.5
\end{array}\
\text { These data are summarized on the following histogram: }
\end{array}$$

Using technology, perform the following hypothesis test: at the 5% significance level,determine Whether the fill volume is less than the supposed value. Comment on the appropriateness of the Test.
A) Test statistic: $t = - 1.8063$; Critical value: $- 2.0921$. Since the test statistic is greater than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. The conclusion is on sound statistical ground.
B) Test statistic: $t = - 1.8063$; Critical value: $- 1.7254$. Since the test statistic is less than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu =$ $16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion.
C) Test statistic: $t = - 1.8063$; Critical value; $- 2.0921$. Since the test statistic is greater than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion.
D) Test statistic: $t = - 1.8063$; Critical value: $- 1.729$. Since the test statistic is less than the critical value, reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is sufficient evidence to conclude that the fill volume is below $16.2 \mathrm { oz }$. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion.

Question

Solve the problem. Use the critical-value approach.
-A machine that fills soda bottles is supposed to fill them to a mean volume of 16.2 fluid ounces. A random sample of 20 filled bottles produced the following volumes in fluid ounces: $$\begin{array}{l}
\begin{array} { l l l l l l l l l l } 
16.3 & 15.9 & 16.7 & 15.3 & 17.1 & 16.4 & 3.9 & 15.9 & 16.2 & 3.4 \
16.4 & 8.2 & 15.5 & 16.5 & 16.0 & 16.3 & 15.8 & 16.7 & 16.5 & 15.5
\end{array}\
\text { These data are summarized on the following histogram: }
\end{array}$$

Using technology, perform the following hypothesis test: at the 5% significance level,determine Whether the fill volume is less than the supposed value. Comment on the appropriateness of the Test. 
A) Test statistic: $t = - 1.8063$; Critical value: $- 2.0921$. Since the test statistic is greater than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. The conclusion is on sound statistical ground. 
B) Test statistic: $t = - 1.8063$; Critical value: $- 1.7254$. Since the test statistic is less than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu =$ $16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion. 
C) Test statistic: $t = - 1.8063$; Critical value; $- 2.0921$. Since the test statistic is greater than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion. 
D) Test statistic: $t = - 1.8063$; Critical value: $- 1.729$. Since the test statistic is less than the critical value, reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is sufficient evidence to conclude that the fill volume is below $16.2 \mathrm { oz }$. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion.

Quizplus · Accepted Answer

The Answer of Solve the problem. Use the critical-value approach.
-A machine that fills soda bottles is supposed to fill them to a mean volume of 16.2 fluid ounces. A random sample of 20 filled bottles produced the following volumes in fluid ounces: $$\begin{array}{l}
\begin{array} { l l l l l l l l l l } 
16.3 & 15.9 & 16.7 & 15.3 & 17.1 & 16.4 & 3.9 & 15.9 & 16.2 & 3.4 \
16.4 & 8.2 & 15.5 & 16.5 & 16.0 & 16.3 & 15.8 & 16.7 & 16.5 & 15.5
\end{array}\
\text { These data are summarized on the following histogram: }
\end{array}$$

Using technology, perform the following hypothesis test: at the 5% significance level,determine Whether the fill volume is less than the supposed value. Comment on the appropriateness of the Test. 
A) Test statistic: $t = - 1.8063$; Critical value: $- 2.0921$. Since the test statistic is greater than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. The conclusion is on sound statistical ground. 
B) Test statistic: $t = - 1.8063$; Critical value: $- 1.7254$. Since the test statistic is less than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu =$ $16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion. 
C) Test statistic: $t = - 1.8063$; Critical value; $- 2.0921$. Since the test statistic is greater than the critical value, do not reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is insufficient evidence to conclude that the fill volume is below $16.2$ oz. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion. 
D) Test statistic: $t = - 1.8063$; Critical value: $- 1.729$. Since the test statistic is less than the critical value, reject the null hypothesis $\mathrm { H } _ { 0 } : \mu = 16.2 \mathrm { oz }$. There is sufficient evidence to conclude that the fill volume is below $16.2 \mathrm { oz }$. However, the data exhibits 3 outliers. Elimination of these outliers may alter the conclusion.

Solve the Problem Using Technology, Perform the Following Hypothesis Test: at the 5