Exhibit 13-3 Consider the following reaction and the corresponding time-concentration table to answer the following question(s) . C₂H₄ (g) + O₃ (g) →C₂H₄O (g) + O₂ (g) The concentration of ozone, O₃, was monitored for this reaction as a function of time and is given in the table that follows.
-Refer to Exhibit 13-3. What is the average rate for the time interval from 40.0 seconds tO₆0 seconds?

Question

Exhibit 13-3 Consider the following reaction and the corresponding time-concentration table to answer the following question(s) . C₂H₄ (g) + O₃ (g) →C₂H₄O (g) + O₂ (g) The concentration of ozone, O₃, was monitored for this reaction as a function of time and is given in the table that follows.

Exhibit 13-3 Consider the following reaction and the corresponding time-concentration table to answer the following question(s) . C<sub>2</sub>H<sub>4</sub> (g) + O<sub>3</sub> (g) →C<sub>2</sub>H<sub>4</sub>O (g) + O<sub>2</sub> (g) The concentration of ozone, O<sub>3</sub>, was monitored for this reaction as a function of time and is given in the table that follows. -Refer to Exhibit 13-3. What is the average rate for the time interval from 40.0 seconds tO<sub>6</sub>0 seconds? A) 1.50×10<sup> - 7</sup> M/s B) 6.25×10<sup> - 7</sup> M/s C) 1.10×10<sup> - 5</sup> M/s D) 1.25×10<sup> - 5</sup> M/s E) 1.40×10<sup> - 5</sup> M/s

-Refer to Exhibit 13-3. What is the average rate for the time interval from 40.0 seconds tO₆0 seconds?

Quizplus · Accepted Answer

To calculate the average rate, we need to use the formula:

Average rate = Δ[O3]/Δt
where Δ[O3] = change in concentration of O3 and Δt = change in time.

For the time interval from 40.0 seconds to 60.0 seconds, the change in concentration of O3 is:

Δ[O3] = [O3]60.0 s - [O3]40.0 s = 0.0400 M - 0.0550 M = -0.0150 M

The negative sign indicates that the concentration of O3 is decreasing over time.

The change in time is:

Δt = 60.0 s - 40.0 s = 20.0 s

Substituting these values into the formula, we get:

Average rate = Δ[O3]/Δt = (-0.0150 M)/(20.0 s) = -7.50×10^-4 M/s

Since the question asks for the absolute value of the average rate, the answer is:

1.50×10^-7 M/s, or choice A.

Exhibit 13-3 Consider the Following Reaction and the Corresponding Time-Concentration