Consider the following reaction:
2 HCl (g)
H₂ (g) + Cl₂ (g) Given the following table for the standard Gibbs Free Energy of formation for each substance in the previous reaction, what is the equilibrium constant, K , for this reaction at 298 K?
Substance D G f (kJmol - 1 ) HCl (g) - 95.30 H₂ (g) 0 Cl₂ (g) 0
A) K = 3.75×10 - 34
B) K = 1.94×10 - 17
C) K = 0.926
D) K = 5.17×1016
E) K = 2.67×1033
Correct Answer:
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