If a gas at 15 atm occupying 5.0 L at 25°C is pressurized to 25 atm at 10 L, what will the new temperature of the gas be?

Question

Quizplus · Accepted Answer

To find the new temperature of the gas, we can use the combined gas law, which is $P_1V_1/T_1 = P_2V_2/T_2$, where $P$ is pressure, $V$ is volume, and $T$ is temperature in Kelvin. First, convert the initial temperature to Kelvin: $25°C + 273 = 298K$. Then, rearrange the formula to solve for $T_2$: $T_2 = (P_2V_2T_1)/(P_1V_1)$. Plugging in the values gives $T_2 = (25 \times 10 \times 298) / (15 \times 5) = 2980K$. Converting back to Celsius: $2980K - 273 = 83.3°C$.

If a Gas at 15 Atm Occupying 5