If a gas at 25.0 atm and 10.0L at a temperature of 15.0°C is pressurized to 30 atm and heated to 20°C, what is its new volume?

Question

Quizplus · Accepted Answer

Using the combined gas law, $P_1V_1/T_1 = P_2V_2/T_2$, where $P$ is pressure, $V$ is volume, and $T$ is temperature in Kelvin. Convert temperatures to Kelvin: $T_1 = 15.0°C + 273.15 = 288.15K$ and $T_2 = 20°C + 273.15 = 293.15K$. Solve for $V_2$: $V_2 = \frac{P_1V_1T_2}{P_2T_1} = \frac{25.0 \times 10.0 \times 293.15}{30 \times 288.15} \approx 11.1L$.

If a Gas at 25