What is the pressure of a gas, when it is started at 18.0 atm, 3.0 L, and 25°C, and expanded to 12.0 L and heated to 35°C?

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Quizplus · Accepted Answer

The pressure of the gas can be found using the combined gas law, which is $P_1V_1/T_1 = P_2V_2/T_2$, where $P$ is pressure, $V$ is volume, and $T$ is temperature in Kelvin. Converting the temperatures to Kelvin gives 298K (25°C + 273) and 308K (35°C + 273). Plugging in the values: $18.0 \text{ atm} \times 3.0 \text{ L} / 298 \text{ K} = P_2 \times 12.0 \text{ L} / 308 \text{ K}$. Solving for $P_2$ gives approximately 6.30 atm.

What Is the Pressure of a Gas, When It Is