How many grams of helium gas are in a 4.0 L container at 25.0 atm, at 0°C?

Name: How many grams of helium gas are in a 4.0 L container at 25.0 atm, at 0°C?
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Quizplus · Accepted Answer

Using the ideal gas law, PV = nRT, we can solve for n (moles of gas). Given P = 25.0 atm, V = 4.0 L, R = 0.0821 L·atm/mol·K, and T = 273 K, we find n = (25.0 * 4.0) / (0.0821 * 273) ≈ 4.46 moles. The molar mass of helium is 4.00 g/mol, so the mass is 4.46 moles * 4.00 g/mol = 17.9 g.

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