When a gas with conditions 12.0 atm, 5.0 L, and 25°C is increased in volume to 10.0 L and heated to 30.0°C, what is its new pressure?

Question

Quizplus · Accepted Answer

Using the combined gas law: (P1 * V1) / T1 = (P2 * V2) / T2, where T is in Kelvin. Convert temperatures to Kelvin (25°C = 298 K, 30°C = 303 K). Solve for P2: P2 = (P1 * V1 * T2) / (T1 * V2) = (12.0 atm * 5.0 L * 303 K) / (298 K * 10.0 L) = 7.20 atm.

When a Gas with Conditions 12