Predict the approximate equilibrium constant (as a power of 10) for the reaction.
$$\left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCH } _ { 2 } \mathrm { SH } + \mathrm { CH } _ { 3 } \mathrm { C } \equiv \overline { \mathrm { C } } : \mathrm { Na } ^ { + } \Longrightarrow \left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCH } _ { 2 } \mathrm {~S} ^ { - } \mathrm { Na } ^ { + } + \mathrm { CH } _ { 3 } \mathrm { C } \equiv \mathrm { CH }$$

Question

Predict the approximate equilibrium constant (as a power of 10) for the reaction.
 $$\left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCH } _ { 2 } \mathrm { SH } + \mathrm { CH } _ { 3 } \mathrm { C } \equiv \overline { \mathrm { C } } : \mathrm { Na } ^ { + } \Longrightarrow \left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCH } _ { 2 } \mathrm {~S} ^ { - } \mathrm { Na } ^ { + } + \mathrm { CH } _ { 3 } \mathrm { C } \equiv \mathrm { CH }$$

Quizplus · Accepted Answer

The Answer of Predict the approximate equilibrium constant (as a power of 10) for the reaction.
 $$\left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCH } _ { 2 } \mathrm { SH } + \mathrm { CH } _ { 3 } \mathrm { C } \equiv \overline { \mathrm { C } } : \mathrm { Na } ^ { + } \Longrightarrow \left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { CHCH } _ { 2 } \mathrm {~S} ^ { - } \mathrm { Na } ^ { + } + \mathrm { CH } _ { 3 } \mathrm { C } \equiv \mathrm { CH }$$

Predict the Approximate Equilibrium Constant (As a Power of 10)