If an enzyme rate increases 10-fold for every 5.7 kJ/mol decrease in the energy of activation, what rate increase would be observed if three H-bonds were stabilizing the transition state with each H-bond having a strength of 21 kJ/mol?

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Quizplus · Accepted Answer

Each H-bond decreases the activation energy by 21 kJ/mol, so three H-bonds decrease it by 63 kJ/mol. Since the rate increases 10-fold for every 5.7 kJ/mol decrease, the rate increase is 10^(63/5.7) = 10^11.

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