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The Ostwald Process Converts Ammonia (NH3)to Nitric Oxide (NO)by Reaction

Question 6

Multiple Choice

The Ostwald process converts ammonia (NH3) to nitric oxide (NO) by reaction with oxygen in the presence of a catalyst at high temperatures.In a test of the process a reaction vessel is initially charged with 4.80 mol NH3(g) and 5.80 mol O2(g) ,sealed,and heated at a fixed high temperature.When equilibrium is established the reaction mixture is analyzed and found to contain 3.80 mol NO(g) .What is the quantity of NH3(g) in the equilibrium reaction mixture?
4NH3(g) + 5O2(g) The Ostwald process converts ammonia (NH<sub>3</sub>) to nitric oxide (NO) by reaction with oxygen in the presence of a catalyst at high temperatures.In a test of the process a reaction vessel is initially charged with 4.80 mol NH<sub>3</sub>(g) and 5.80 mol O<sub>2</sub>(g) ,sealed,and heated at a fixed high temperature.When equilibrium is established the reaction mixture is analyzed and found to contain 3.80 mol NO(g) .What is the quantity of NH<sub>3</sub>(g) in the equilibrium reaction mixture? 4NH<sub>3</sub>(g) + 5O<sub>2</sub>(g)    4NO(g) + 6H<sub>2</sub>O(g)  A) 1 mol NH<sub>3</sub>(g)  B) 8.6 mol NH<sub>3</sub>(g)  C) 4.8 mol NH<sub>3</sub>(g)  D) 1.05 mol NH<sub>3</sub>(g)  E) 2 mol NH<sub>3</sub>(g)
4NO(g) + 6H2O(g)


A) 1 mol NH3(g)
B) 8.6 mol NH3(g)
C) 4.8 mol NH3(g)
D) 1.05 mol NH3(g)
E) 2 mol NH3(g)

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