For the reaction Br₂(g)+ Cl₂(g) 2BrCl(g),at equilibrium,it is found that the concentrations of Br₂,Cl₂,and BrCl are 0.484 M,0.105 M,and 1.24 × 10^-3 M,respectively.What is the value of K_c?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the given reaction is:
Br2(g) + Cl2(g) ⇌ 2BrCl(g)
The equilibrium constant expression is:
Kc = [BrCl]2/([Br2][Cl2])
Substituting the given values and solving, we get:
Kc = (1.24 × 10^-3)^2 / (0.484 × 0.105) = 3.01 × 10^-5
Therefore, the answer is choice A.

For the Reaction Br2(g)+ Cl2(g) 2BrCl(g),at Equilibrium,it Is Found

For the Reaction Br₂(g)+ Cl₂(g) 2BrCl(g),at Equilibrium,it Is Found