A sample of ammonia gas was allowed to come to equilibrium at 400 K.
2NH₃(g)
N₂(g) + 3H₂(g)
At equilibrium,it was found that the concentration of H₂ was 0.0484 M,the concentration of N₂ was 0.0161 M,and the concentration of NH₃ was 0.295 M.What was the initial concentration of ammonia?

Question

A sample of ammonia gas was allowed to come to equilibrium at 400 K.
2NH₃(g)

A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH<sub>3</sub>(g) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) At equilibrium,it was found that the concentration of H<sub>2</sub> was 0.0484 M,the concentration of N<sub>2</sub> was 0.0161 M,and the concentration of NH<sub>3</sub> was 0.295 M.What was the initial concentration of ammonia? A) 0.161 M B) 0.228 M C) 0.36 M D) 0.311 M E) 0.328 M

N₂(g) + 3H₂(g)
At equilibrium,it was found that the concentration of H₂ was 0.0484 M,the concentration of N₂ was 0.0161 M,and the concentration of NH₃ was 0.295 M.What was the initial concentration of ammonia?

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The Answer of A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH₃(g) N₂(g)+ 3H₂(g) At equilibrium,it was found that the concentration of H₂ was 0.0484 M,the concentration of N₂ was 0.0161 M,and the concentration of NH₃ was 0.295 M.What was the initial concentration of ammonia?

A Sample of Ammonia Gas Was Allowed to Come to Equilibrium