On analysis, an equilibrium mixture for the reaction 2H₂S(g) 2H₂(g)+ S₂(g)was found to contain 1.0 mol H₂S, 4.0 mol H₂, and 0.80 mol S₂ in a 4.0 L vessel.Calculate the equilibrium constant, K_c, for this reaction.

Question

Quizplus · Accepted Answer

We can write the expression for the equilibrium constant, Kc, as: Kc = [S₂][H₂]^2 / [H₂S]^2 Substituting the values: Kc = (0.80 × 4.0 × 4.0) / (1.0 × 1.0 × 1.0) Kc = 12.8 Therefore, the answer is (C).

On Analysis, an Equilibrium Mixture for the Reaction 2H2S(g)

On Analysis, an Equilibrium Mixture for the Reaction 2H₂S(g)