K_p for the reaction CO₂(g)+ C(s) 2CO(g)is 1.47 at 727°C.Calculate K_c at this temperature

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is:

Kc = ([CO]^2)/([COS][CO2])

We can use the given equilibrium constant (Kp = 1.47) to calculate Kc as follows:

Kp = Kc(RT)^Δn

where Δn is the difference in the number of moles of gaseous products and reactants (Δn = (2+0) - (1+1) = 0).

Substituting the values:

1.47 = Kc(0.0821 x 727)^(0)

Kc = 1.47/59.99

Kc = 0.0246 (approximately)

Therefore, the correct answer is (D) 0.0246.

Kp for the Reaction CO2(g)+ C(s) 2CO(g)is