What mass of phosphoric acid (H₃PO₄,98.00 g/mol)is produced from the reaction of 10.00 g of P₄O₁₀ (283.89 g/mol)with 12.00 g water (18.02 g/mol)?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is: P₄O₁₀ + 3H2O → H₃PO₄ + H3O+ + OH- First, we need to calculate the number of moles of P₄O₁₀: n(P₄O₁₀) = m/M = 10/283.89 = 0.03525 mol Since P₄O₁₀ is limiting, we need to use its mole ratio with H₃PO₄ to find the number of moles of H₃PO₄: n(H₃PO₄) = n(P₄O₁₀) × (1 mol H₃PO₄ / 1 mol P₄O₁₀) = 0.03525 mol Now we can use the molar mass of H₃PO₄ to find its mass: m(H₃PO₄) = n(H₃PO₄) × M(H₃PO₄) = 0.03525 mol × 98.00 g/mol = 3.4515 g Therefore, the mass of H₃PO₄ produced is 3.4515 g, which rounds to 3.45 g. However, we must also check the mass of water to ensure that it is not limiting. n(H2O) = m/M = 12.00/18.02 = 0.6663 mol n(P₄O₁₀) / n(H2O) = 0.03525 mol / 0.6663 mol = 0.0528 mol of P₄O₁₀ per mol of H2O Since this ratio is less than 3, which means the water is not limiting, the answer is 3.45 g.

What Mass of Phosphoric Acid (H3PO4,98

What Mass of Phosphoric Acid (H₃PO₄,98