Hydrochloric Acid (HCl) Reacts with Sodium Hydroxide (NaOH) to Form $\Delta$

Hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water. If $\Delta$ H ^$\circ$ = -56.13 kJ/mol and $\Delta$ S ^$\circ$ = 79.11 J/mol . K, what is $\Delta$ G ^$\circ$ for this reaction at 20 ^$\circ$ C?

A) (-79.31 kJ/mol)
B) (-77.73 kJ/mol)
C) (-2.324 $\times$ 10⁴ kJ/mol)
D) 79.31 kJ/mol
E) (-1,638 kJ/mol)