Hydrochloric Acid (HCl) Reacts with Sodium Hydroxide (NaOH) to Form $\Delta$

Hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water. If $\Delta$ H ^$\circ$ -56.13 kJ/mol and $\Delta$ S ^$\circ$ = 79.11 J/mol . K, what is the temperature of the reaction if $\Delta$ G ^$\circ$ = -80.89 kJ/mol?

A) 154 ^$\circ$ C
B) 313 ^$\circ$ C
C) 0.313 ^$\circ$ C
D) 40.0 ^$\circ$ C
E) 75 ^$\circ$ C