Hydrochloric Acid (HCl) Reacts with Sodium Hydroxide (NaOH) to Form $\Delta$

Hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water. If $\Delta$ H° = -56.13 kJ/mol and $\Delta$ S° = 79.11 J/mol · K, what is $\Delta$ G° for this reaction at 20°C?

A) -79.31 kJ/mol
B) -77.73 kJ/mol
C) -2.324 * 10⁴ kJ/mol
D) 79.31 kJ/mol
E) -1638 kJ/mol