O₂ can be produced by the reaction 2KClO₃(s) → 2KCl(s) + 3O₂(g). In one experiment, 0.312 g of O₂ was formed. How much KCl was produced?

Question

Quizplus · Accepted Answer

Given the stoichiometry of the reaction, 2 moles of KCl are produced for every 3 moles of O2. First, find the moles of O2 produced using its molar mass (32 g/mol): 0.312 g / 32 g/mol = 0.00975 moles. Then, calculate the moles of KCl produced: (2/3) * 0.00975 moles = 0.0065 moles. Finally, find the mass of KCl using its molar mass (74.55 g/mol): 0.0065 moles * 74.55 g/mol = 0.484 g.

O2 Can Be Produced by the Reaction 2KClO3(s) → 2KCl(s)

O₂ Can Be Produced by the Reaction 2KClO₃(s) → 2KCl(s)