The energy needed to remove an electron from the first excited state of a Li2+ ion is:
A)53 eV
B)31 eV
C)92 eV
D)122 eV
E)61 eV

Question

Quizplus · Accepted Answer

The energy required to remove an electron from the first excited state of a Li2+ ion can be calculated using the formula for ionization energy of hydrogen-like ions: E = -13.6 * Z^2 / n^2 eV, where Z is the atomic number (3 for Li) and n is the principal quantum number (2 for the first excited state). This gives E = -13.6 * 3^2 / 2^2 = -30.6 eV, which is approximately 31 eV.

The Energy Needed to Remove an Electron from the First