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The Equilibrium Constant for the Reaction Below Is 1

Question 1

Multiple Choice

The equilibrium constant for the reaction below is 1.7*1017 at 25 C.
H₂ (g) + Br₂(g) The equilibrium constant for the reaction below is 1.7*10<sup>17</sup> at 25 C. H₂ (g)  + Br₂(g)    2 HBr (g)  K c (25 C)  = 1.7*10<sup>17 </sup> What can be stated about the relative equilibrium distribution for this mixture? A)  The mixture contains predominantly H<sub>2</sub> at equilibrium. B)  The mixture contains predominantly Br<sub>2 </sub>at equilibrium. C)  The mixture contains predominantly HBr at equilibrium. D)  The mixture contains predominantly H<sub>2</sub> and Br<sub>2 </sub>at equilibrium. E)  The mixture contains relatively equal amounts of H<sub>2</sub>, Br<sub>2</sub> and HBr at equilibrium. 2 HBr (g) K c (25 C) = 1.7*1017
What can be stated about the relative equilibrium distribution for this mixture?


A) The mixture contains predominantly H2 at equilibrium.
B) The mixture contains predominantly Br2 at equilibrium.
C) The mixture contains predominantly HBr at equilibrium.
D) The mixture contains predominantly H2 and Br2 at equilibrium.
E) The mixture contains relatively equal amounts of H2, Br2 and HBr at equilibrium.

Correct Answer:

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