If the free-energy change of a voltaic cell is -258 kJ, what is the potential of the cell if three moles of electrons are transferred in the oxidation-reduction reaction?

Question

Quizplus · Accepted Answer

The free-energy change of a voltaic cell is related to the cell potential by the equation:

ΔG = -nFE

Where ΔG is the free-energy change, n is the number of moles of electrons transferred, F is the Faraday constant (96,485 C/mol e-), and E is the cell potential.

Rearranging this equation gives:

E = -ΔG/nF

Substituting the given values:

E = -(258,000 J/mol)/(3 mol)(96,485 C/mol e-)

E = -0.890 V

The negative sign indicates that the reaction is spontaneous in the reverse direction. However, the question is asking for the potential of the cell, which is the opposite of the calculated value. Therefore, the answer is:

A) (F1F1F1S1F1F1F100.890 V)

If the Free-Energy Change of a Voltaic Cell Is -258