Considering that PV = nRT, which one of these samples contains the smallest number of particles?
STP = 0 $\circ$ C and 1 atm.

Question

Considering that PV = nRT, which one of these samples contains the smallest number of particles? 
STP = 0 $\circ$ C and 1 atm.

Quizplus · Accepted Answer

Given the ideal gas law PV=nRT, where n is the number of moles (directly proportional to the number of particles), and the conditions of STP (Standard Temperature and Pressure) are 0°C and 1 atm, the number of particles in a gas sample is determined by its volume, temperature, and pressure. All options except C are at STP, meaning they have the same temperature and pressure, so their number of particles would be directly proportional to their volumes, which are the same. Option C, however, is at the same volume but a higher temperature (25°C) and the same pressure as STP, which means it would have a slightly larger volume if it were at STP due to the increase in temperature. Since the volume is fixed at 2.0 L but the conditions are not STP, the number of particles in the sample would be less due to the increased kinetic energy and, consequently, an increased volume if it were allowed to expand. This makes C the correct choice because the conditions specified (25°C and 760 torr) do not change the number of particles directly, but under STP conditions, this sample would occupy a larger volume, indicating fewer particles in the 2.0 L volume at the given conditions.

Considering That PV = NRT, Which One of These Samples ∘\circ∘

Considering That PV = NRT, Which One of These Samples $\circ$