A food sample was burned in a bomb calorimeter containing 524 mL water. How much thermal energy was produced when the temperature of the water and the calorimeter rose from 20.0 $\circ$ C to 25.0 $\circ$ C? The metal calorimeter had a heat capacity of 725 J/ $\circ$ C without the water. The specific heat capacity of water is 4.184 J/(g $\circ$ C).

Question

Quizplus · Accepted Answer

First, calculate the mass of water in the calorimeter:

524 mL = 0.524 L
density of water = 1 g/mL
mass of water = 0.524 kg

Next, calculate the change in temperature:

ΔT = 25.0°C - 20.0°C = 5.0°C

Then, calculate the thermal energy produced:

q = (mwater + mcalorimeter) * C * ΔT
q = (0.524 kg + 0.725 kg) * 4.184 J/(g°C) * 5.0°C
q = 14.6 kJ

Therefore, the thermal energy produced is 14.6 kJ. Choice B is the correct answer.

A Food Sample Was Burned in a Bomb Calorimeter Containing ∘\circ∘

A Food Sample Was Burned in a Bomb Calorimeter Containing $\circ$